I have a question regarding the molecular orbitals of water. I have to show the molecular orbitals of water as derived from s and p orbitals that are responsible for the "lone pair character" in water. Now, i have the electronic structure of water as 1a
122a
121b
223a
121b
12. I derived this from the Character table for C
2v, finding the symmetry adapted linear combinations for the 2 hydrogen 1s orbitals. The orbitals have been arranged in energy order according to data from lsbu.ac.uk/water (a reliable source).
I know for definite that the 1b
1 orbital (mainly p
x character) is not involved in the sigma bonds and is responsible for the "lone pair" effect on oxygen. However, having constructed the MO correlation diagram according to the rules in "Group Theory for Chemists", i see that the other non-bonding orbital is 2a
1, which is not responsible for lone pair character. The lone pair character comes from 3a
1, but according to the MO diagram (and other data) this orbital is also involved in bonding. How can i explain that this is the orbital responsible for lone pair character when it is involved in bonding?
The 3a
1 orbital is made from p
z and the two hydrogen s orbitals. Theoretically the 2s on oxygen is also involved, if i mixed this in, this results in 3 mixed MOs of a
1. Does this mean that the middle orbital (3a
1) is non-bonding and appears as such (i think this diagram looks more correct, esp. if you consider the energies of the orbitals shown at the side)?
On a side note, would the fact that removal of electrons from these orbitals by XPS does not cause dissociation of the molecule be evidence that the electrons are in fact the lone pair and not bonding electrons?