A mixture containing KClO3, K2CO3, KHCO3, and KCl was heated, producing CO2, O2, and H2O gases according to the following reactions:
2KClO3(s) → 2KCl(s) + 3O2(g)
2KHCO3(s) → K2O(s) + H2O(g) + 2CO2(g)
K2CO3(s) → K2O(s) + CO2(g)
The KCl does not react under the conditions of the reaction. If 100.0 g of the mixture produces 1.80 g of H2O, 13.20 g of CO2, and 4.00 g of O2, what was the composition of the original mixture? (Assume complete decomposition of the mixture.)
i've successfully gotten the amount of KClO3 & KHCO3; however, K2CO3 is giving me trouble (i'm thinking that maybe K2O is the limiting reagent, but how do i get that?)
*point the arrow the other way to make it look like a regular Limiting Reactant problem.
answers: KClO3 = 10.2g, KHCO3 = 20.0g, K2CO3 = 13.8g (eh? idk why i'm not getting it), KCl does not react so it's just 100g - (KClO + KHCO3 + K2CO3) = 56.0g
thanks for any help