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Topic: Draw major products  (Read 7817 times)

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Offline a confused chiral girl

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Draw major products
« on: June 10, 2007, 05:03:44 PM »
Hi everyone :)

I have 2 questions which are asking to predict the major products. I have already gave them both a try, and the 2 structures that are drawn in blue are my predicted products. the black ones are what is given.
In #1, I am thinking that only Br gets affected, but should NH also get affected as well? I don't think so..because Br is a much better leaving group. Please correct me if I'm wrong  ::)

In #2, I think an alkane like the one I have drawn is going to be the major product. correct?

thank you everyone!

Offline a confused chiral girl

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Re: Draw major products
« Reply #1 on: June 12, 2007, 02:19:39 AM »
For the second reaction, would equivalents of CH3OH make a difference in the product?  right now, the reageants are CH3OH, H+. I'm not sure if there are going to be 2 OCH3 adding on the carbon, or just one OCH3 and one H..

Offline Fry

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Re: Draw major products
« Reply #2 on: June 12, 2007, 02:32:01 AM »
The second one looks like it will be a transesterification.. you'll end up with a methyl ester.


The first looks good.. I dont know how easily that amine may deprotonate to destroy the grignard though.

Offline a confused chiral girl

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Re: Draw major products
« Reply #3 on: June 12, 2007, 02:47:31 AM »
The second one looks like it will be a transesterification.. you'll end up with a methyl ester.

do you mean this when you say methyl ester? so ...the C is attached to one OCH3 and one OH? instead of 2 OCH3?
thanks~

Offline Fry

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Re: Draw major products
« Reply #4 on: June 12, 2007, 02:51:27 AM »
No, I mean you'll end up with methyl ethanoate..

CH3CO2CH3

Offline AWK

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Re: Draw major products
« Reply #5 on: June 12, 2007, 06:17:53 AM »
Note, in the first reaction a Grignard reagent can react with ortho-ester (at least side product wiil be formed)
AWK

Offline chengyang79

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Re: Draw major products
« Reply #6 on: June 12, 2007, 07:24:40 AM »
I think that the Hydrogen atom of the pyrrole ring is an active one, so the grignard reaction can't initiated. and also,grignard reagent may attack the -C(OMe)3 group that is lead to an corresponding dimethylacetal.

The second one ,the reactant be in equilibrium with product.Yield a mixtrue of ethylacetate and methyl-acetate .

Offline english

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Re: Draw major products
« Reply #7 on: June 12, 2007, 11:05:18 AM »
You haven't downloaded that drawing program yet?  ;)

Offline gtaskiran1977

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Re: Draw major products
« Reply #8 on: June 13, 2007, 11:49:34 AM »
The second predict is too strong . 1-Carbonyl groupe =OH+  2-OCH3 attack so -OH and OCH3 connect the same carbon. 3- Second H+ connect -OH group( -OH2+) Its sigma electrons do a = bond and H+(Catalys) to be regenarate. H2C=COCH3OC2H5 (IN MY OPINION, MAY BE?)

Offline gtaskiran1977

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Re: Draw major products
« Reply #9 on: June 13, 2007, 04:04:45 PM »
I think that first reaction very strong. Because pirol is an aromatic compound. And in this structure, Brom is an electron donör in view of mesomerically and resonance form of pyrrole is not suitable on Br-C=. And the other(3. position) is more suitable for this problem. 

Offline organoman

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Re: Draw major products
« Reply #10 on: June 14, 2007, 03:29:06 AM »
I think both reactions are right. Secand one is an example of acid catalysed ketal formation

Offline AWK

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Re: Draw major products
« Reply #11 on: June 14, 2007, 06:43:46 AM »
Second one is an example of acid catalysed ketal formation
The first reagent in this reaction is an ester not a ketone
AWK

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