[kadaj]

Hi everybody,

If a solution A contains 100mg of quanine sulfate and it dissolved in 100ml of 0.5M of sulfuric acid and the second solution, solution B was made up by diluting 10ml of solution A using 0.5M sulfuric acid and made up 100ml, calculate the new concentration.

Using this value, solution C was made up by diluting 10ml of solution B and made it up to 25ml, calculate the new concentration for solution C.

Thank you

[sdekivit]

first: 100 mg in 100 mL solution (= solution A): concentration = ?

--> then: solution B is 10 mL A to 100 mL solution: dilution factor = ? and use that to calculate the new concentration.

--> then: solution C = 10 mL B to 25 mL solution: dilution factor = ? --> concentration = ?

[kadaj]

Sorry, but I meant using mol/L units

I tried this using C₁V₁=C₂V₂ formula and I ended up with 5M for concentration in solution A, 0.5M for solution B and 0.2M for solution C, please correct me if im wrong

Thank you

[AWK]

solution B 100/10=10 times diluted
solution C 25/10 = 2.5 times
hence solution C is 25 times diluted with regards to solution A (you can use any units of concentration for solution A)

[kadaj]

Cheers mate  that helps