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Topic: calculating the weight  (Read 3394 times)

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Offline shylight200

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calculating the weight
« on: September 05, 2007, 08:43:42 PM »
calculate the weight of Na2CO3 needed to react with 25 mL of 0.1 M HCl


can someone please help me get started? thanks
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Offline Yggdrasil

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Re: calculating the weight
« Reply #1 on: September 05, 2007, 08:56:10 PM »
Always start with a balanced chemical reaction.
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Offline shylight200

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Re: calculating the weight
« Reply #2 on: September 05, 2007, 09:00:23 PM »
ok, i wrote the equation and got a 2 to 1 ratio

so i did:
(0.1 mol HCl)/(1 L) * (1 L)/(1000 mL) * 25 mL * (1 Na2CO3)/(2 HCl) * (106 g)/ (1 mol) and i got 0.1324 g of Na2CO3

is this right?
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Offline Yggdrasil

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Re: calculating the weight
« Reply #3 on: September 05, 2007, 11:11:59 PM »
Looks right to me.  Good job.
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