In the simplest, 'most' ideal case, Raoult's law defines the vapour pressure of the system as a function of the composition (x, mole fraction) of the liquid phase. For a mixture of two substances A and B:
pA = pA° * xA
pB = pB° * xB = pB° * (1-xA)
where the p°'s are the vapour pressure of the pure A and B.
Therefore, the total pressure of the system will be:
P = pA + pB = (pA° - pB°)*xA + pB°
You know that the liquid boils when P = Pext, where Pext is the pressure applied to your system (often 1 atm).
But from the equation above it's clear that P depends on pA° and pB°, and these in turn depend on the temperature. In the simplest case you can write:
ln p° = a - b/T
where a and b are experimental parameters.
If you write this for both A and B, solve for p° and substitute in the original equation, you will get a very complex expression that can not be solved symbolically for T.
So the short answer is: no, even in the simplest case you can't calculate the boiling point of a mixture from the boiling points of the components. And even if you introduce further data, like the a and b parameters shown above, you may need a numerical or graphical method to have your answer.
But you should ask a physical chemist, just to be sure.