Hey all. I really need some help with a lab sheet I need to turn in. Our instructor handed out a few unknown metals to each of our lab groups. The goal was for us to identify the metal and I am having some real trouble. The mass of the sample was 17.75g. The mass of the calorimeter was 9.10. The mass of the calorimeter + water = 55.55g, so the mass of the water = 46.45 g. The initial water temp was 21.5C, temperature of heated metal sample was 88C, final temperature of water and metal 25.8 C, so I calculated the change in water temp to be 4.3, change in temp of the metal sample 62.2. Specofoc heat of water is 4.184 J/g C. First they want... the heat gained by the water... so i set my equation as follows. (46.45)(4.184)(4.3)=8.36x10^2 ... the lab manual said that heat gained by water is equal to the heat lost by metal. So the heat lost by the metal would also be 8.36x10^2. Finally they want the specific heat of the metal. I set my equation up as follows.... 8.36x10^2 / (17.75)(62.2) = 10.95 J/g C . This is not one of the specific heats he gave us for the unknown metals, it is extremely high, we are to get numbers such as .900, .385, .131, .451, .128, .237, .222 Im not sure what I did wrong in calculations to get such a large number. I have gotten A's on all my labs so far and am usually pretty sharp with getting correct data, and our instuctor helped us do the majority of it. Any suggestions? I would really appreciate it. Steph