hello again
i really need help,,, yesterday evening I tried to solve the problems and I have answers ,, about the 1st q. ,,,
I get no. of moles NH4+ in the second 5o ml .. 1.7792*10-3 , and it equals the no. of moles NH4NO3 , then i calculated its percentage by getting its wt 0.42409 then 14.127%
the no. of moles NH4+ in the first 50 ml is 1.3323*10-3 ,,, so in the total 5oo ml equal 0.1332344 moles ,,, then
1.7792*10-3 _ 0.1332344 = 0.11544213 ... and these are no. of moles for NH4+ in (NH4)2SO4
which equals twice no. moles of (NH4)2SO4 ,, then i get its wt. then percentage 75.6672% ,, is this true???
about second q. i calculated no. mols cl- in .1606 g AgCl ,, then In 5 gram which is the grams of sample
I calculated the no. mols of the cpd given in q. by saying 5 mols cl equal 1 mol of cpd ..
and get it wt by multiplying with its fw,, then the % is 49.4697%
plz can any one help me in revising my steps... I tried herd to solve them... and If my ask or my whloe topic is against rules,,, can any one tell me??
thnx alot