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Topic: Ideal Gas Law  (Read 3434 times)

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Offline laxplayer

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Ideal Gas Law
« on: November 04, 2007, 04:46:23 PM »
The question states
 "For an ideal gas, calculate the following quantities: The volume occupied by 5.72*10^-3 mol at 30.°C and a pressure of 1.17 kPa."

The temperature in Kelvin is 303.15, and I found the pressure to be .01155 atm. Then I multiplied (.00572)(.0821)(303.15) to get .142363. I divided .0115 atm by this and got .0808L. I used the ideal gas law PV=nRT to do this, but it keeps coming up as wrong. Does anyone know what i'm doing wrong?
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Offline Borek

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Re: Ideal Gas Law
« Reply #1 on: November 04, 2007, 04:53:01 PM »
Quote from: laxplayer on November 04, 2007, 04:46:23 PM
I divided .0115 atm by this and got .0808L.

Check formula you are using.
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Offline laxplayer

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Re: Ideal Gas Law
« Reply #2 on: November 04, 2007, 04:56:37 PM »
ohhh, you divide it the other way, ha, thanks :]
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