[Atome]

Hello everyone,

I am having trouble with the following problem and I would appreciate any assistance. I have shown my work.

Thank you.

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1. A 9.76 sample of table sugar is placed in a 25.00 mL flask. The flask is completely filled with liquid benzene, and the sugar and benzene have a total mass of 26.31 g. The sugar does not dissolve in the benzene. If the density of benzene is 0.879 g/mL, what is the density of sugar?

Flask = 25.00 mL
m of sugar = 9.76 g
m of benzene = ? (21.975 g)
m of sugar & benzene = 26.31 g
density of benzene = 0.879 g/mL
density of sugar = ?
V of sugar = ?

m of benzene = density x volume

                   = 0.879 g/mL x 25.00 mL

                   = 21.975 g

However, at this point, how would I find the volume of sugar so I can calculate the density fo sugar?

[ARGOS++]

Dear Atome;

You are doing a small Thinking “Mistake”!

Answer the Questions:

• What does the flask contain? –> 9.76g Sugar   and   ?x?g Benzene.
• How much volume is ?x?g Benzene, and how much volume is left for Sugar?

Now you are one step before the “Olympus”.

Good Luck!
                   ARGOS⁺⁺

[Atome]

Dear Argos,

Thanks for your reply. I do not fully understand your reply though.

The flask would contain 9.76 g of sugar and 21.975 g of sugar.

If the volume of benzene is 0.879 g/mL, how would I use that information to find the volume of sugar?

Thanks again!

[ARGOS++]

Dear Atome;

That's exactly your Thinking “Mistake”!

9.76g Sugar +  21.975g Benzen   are NOT:  26.31g (in total!)
You have to go the other way around!

Good Luck!
                   ARGOS⁺⁺

[Atome]

Dear Argos:

Thanks for your reply! The mass of benzene would be 16.55 g then.

How would I use this information to find the density of sugar though?

[ARGOS++]

Dear Atome;

You are right!

Now answer the second question, and you will know the volume of Benzene, and of Sugar (as the difference!).

Good Luck!
                   ARGOS⁺⁺

[Atome]

Dear Argos,

Thank you very much for the *delete me* I got it!