When sodium Chloride is strongly heated in a flame, the flame takes on the yellow color associated with the emission spectrum of sodium atoms. the reaction that occurs in the gaseous state is
Na(g) + Cl- (g) -----> Na (g) + Cl (g)
Calculate delta H for this reaction.
i really need help with the question. even though my teacher solved it a little i still do not understand it.
This is how she did the question.
Na + e ----> Na delta H = - Ii
Cl- --------> Cl + e delta H = - EA
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delta H = delta H1 + Delta H 2
pleaseeeee can anyone explain it to me...