Predict the products of the reaction of 3-bromo-2,3,4-trimethylpentane with hydroxide ion.
Clearly, this cannot react through SN2, b/c the carbon is tertiary. However, it seems reasonable that both an SN1 and E2 reaction are possible to produce 2,3,4-methyl-3-pentanol and 2,3,4-methyl-2-pentene, respectively. The latter product could also be produced through a competing E1 reaction. Can all these mechanisms be taking place simultaneously?
Thank you.