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Topic: Appreciate anyone to help puzzled Dad...  (Read 4310 times)

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Offline phantom747

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Appreciate anyone to help puzzled Dad...
« on: November 29, 2007, 10:53:01 AM »
Dear ChemWizards, my son has a paper for which we could not find the formula in Perry's or Kirk-Othmer, maybe we're deluged by the massive info of both books. ;)

Our dilemma is: for liquids, the less pressure one exerts or goes down near to vacuum, the lower boiling point will be.. right? We've checked our knowledge bit against water/pressure/boiling points, it works that way... The question remains: is there any reliable formula that'll work for any other liquid, so we can calculate the vaporization point of that particular liquid accordingly? Dad, an M.D., could not provide an answer, can you? Appreciate any help...Thanks.. Zaff.

Offline Borek

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Re: Appreciate anyone to help puzzled Dad...
« Reply #1 on: November 29, 2007, 11:17:05 AM »
What do you mean by "vaporization point"?
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Offline invisiblegs

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Re: Appreciate anyone to help puzzled Dad...
« Reply #2 on: November 29, 2007, 02:47:18 PM »
Lets look at this problem in terms of an equilibrium.  It is important to realize that on the molecular level, most things can be described as an overall average of the same molecule in different states.  Here we are talking about two different states being liquid or gas phase molecules.  So, remembering our physics classes, we know that for a balanced system, any pressure acting on a surface must be balanced by an equal and opposite pressure from that surface.  So, as the gas (air) above a liquid surface exerts pressure on the liquid surface, the liquid surface pushes back with an equal pressure.  Part of the pressure that the liquid exerts on the air is generated by molecules of the liquid "trying" to become molecules of gas.  The thermal energy of the liquid molecules will tend to push them apart due to the molecular motion it causes.  As you add heat (thermal energy) to the liquid, the motion of the molecules increases, and the pressure they exert on the air above them also increases.  This is called the vapor pressure of a liquid.  So, what happens when the vapor pressure of a liquid is less than the pressure of the gas above it?  Conversely, what happens when the vapor pressure of the liquid is greater than the gas above it?  By either changing the vapor pressure of the liquid (changing its temperature), or changing the gas pressure above the liquid, we can control the equilibrium of the liquid and gas.  As for predicting these phase change phenomena, a good table of liquid vapor pressures should help. 

Offline Yggdrasil

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Re: Appreciate anyone to help puzzled Dad...
« Reply #3 on: November 29, 2007, 03:47:51 PM »
http://en.wikipedia.org/wiki/Clausius-Clapeyron_Equation#Chemistry

Is this what you're looking for?  Note that the boiling point of a liquid will just be the temperature at which its vapor pressure equals the atmospheric pressure on the liquid.

Offline sondakem

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Re: Appreciate anyone to help puzzled Dad...
« Reply #4 on: December 12, 2007, 11:20:43 AM »
I'm sure the Clausius-Clapeyron equation is the elegant answer.

I just found a P-T alignment chart from the old Matheson Coleman & Bell company.  You place a clear plastic ruler on the BP-760 line. To the left is another line showing observed BP and to the right is another line showing P of observed BP.  By moving the ruler you can get BP at different P.
I think the chart was called a nomograph.

A thing like that should be somewhere on the net.

Offline AWK

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