Kw = [H+][OH-] = 10(10-14)
Correct? Do not take my word for it. Verify it. Learn it!
You know everything but H+, you can solve for it, and then plug that into your pH equation.
Alternatively. You can calculate the pOH, -log([OH-], and take that away from 14.
I.E.
pH = 14 - ( -log ([OH-]) )
Right? Can you reason these out? This all comes from the equilibrium constant of water and then doing math.