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Topic: pH with Ka problem  (Read 5574 times)

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Edher

  • Guest
pH with Ka problem
« on: February 20, 2005, 03:37:41 PM »
Saludos,

    Acetylsalicylic acid, HC9H704, is the active component in an aspirin. This acid is the cause of the stomach upset some people get when taking aspirin. Two extra-strength aspirin-tablets, each containing 500mg of acetylsalicylic acid, are dissolved in 325 mL of water. What is the pH of this solution?  Ka=3.3x10^-4

HC9H7O4 + H2O <-->H3O+ + C9H7O4-


My steps,
- The molar mass of the 1g of aspirin. (0.00555 moles)
- The molarity of aspirin dissolved in water (0.01708 M)
- ICE method.
     x   2 = 3.3x10-4
   0.01708-x
- Quadratic Formula. (x=0.004429)
- Negative Log of x. (2.65)


The right answer is 11.28.

Where did I go wrong?

Thank You in Advance,
Edher

Demotivator

  • Guest
Re:pH with Ka problem
« Reply #1 on: February 20, 2005, 07:58:51 PM »
How can ph 11 be right? It's an acid!  ???

Edher

  • Guest
Re:pH with Ka problem
« Reply #2 on: February 20, 2005, 08:09:02 PM »
Saludos Demotivator,

       It turns out that it was yet another typo. I checked my notes and indeed my professor had pointed it out.

Thank You,
Edher

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