1. pOH=14.00-13.07=0.97
2. [OH-]=10^-0.97=0.12M
3. CxV=n=0.12Mx1.00L=0.12mol
4. B/C 100% ionized n(salt)=n(solution)
5. M=m/n=10.00g/0.12mol=85.11g/mol
For my answer the Molar mass makes sense, but please check if it's correct!
I did the same thing but your calculations are kinda wrong i think...
1. pOH = 14.00 - 13.07 = 0.93
2. [OH-] = 10 ^ -0.93 = 0.117 (don't round this... or else you'll get another answer like 83.33 in the end shown in step 4)
3. CxV=n=0.117Mx1.00L=0.117 mol
4. M=m/n=10.00g/0.117mol=85.47g/mol (if you rounded 0.117 to 0.12 you'll probably get something like..83.33)
Tell me if what I did is right.. i need an answer by Wednesday