[Pero]

Hello!

I have one question about the main quantum numbers n₁ and n₂.

The wave equation for series of waves is in the following form :

1/λ = R (1/n₁² - 1/n₂²)

where R is the Rydberg's constant R = 1,09 * 10⁷.

For the series of UV waves, the quantum numbers are n₁=1 and n₂=2,3,4...

Thanks in advance!

[Borek]

And your question is?

Note: is "wave equation" correct term here? English is my second language so I am not sure, but it doesn't sound good to me. Formula for wavelengths for sure.

[AWK]

Elecron coming back from n=2 to n=1 generates X-ray, not UV radiation

[enahs]

Note: is "wave equation" correct term here? English is my second language so I am not sure, but it doesn't sound good to me. Formula for wavelengths for sure.

Over here in the US we use "wave equation" all the time. Sounds good to be. Silly Polish people  .

[Borek]

We use term "wave equation" as well, we just use it to name the equation that describes the wave, not equation that describes energy of photons emitted from the atom.

[Valdorod]

They call this the wave equation because it is in terms of the wavelegth, whereass

E = -R(1/n²)

is called the energy equation since it is in terms of energy.
Clearly a misnomer, but very common.

It gets confusing for many students because Rydberg's constant has a different value due to the different units used.  For the "energy equation"  it is 2.18 x 10^-18 J.  Thus, due to our lack of better teaching, (or my lack of better teaching) my students often use the wrong one for the wrong equation.  I have tried in previous years to use only one form of the equation and its constant to avoid confusion.


AWK

Since when is the Lymann series x-rays?  From the R given, it is obious that it is for the hydrogen atom.  Lymann is UV (all drops to n=1), Balmer is mostly visible (depending on whether you consider 364 UV or visible) (all falls to n=2), and Paschen is IR , etc, etc.

Calculating from n=2 to n=1 you have an energy of 984.03 kj/mol and a wavelength of 121.56 nm, clearly within the UV range and nowhere near x-rays

Valdo

[AWK]

X-rays are not generated from a hydrogen atom.
X-ray lines K(alpha)s come from 2->1 transition,
lines K(beta)s - from 3->1 transition

[Valdorod]

X-rays are not generated from a hydrogen atom.

Exactly my point
The k alpha line for the hydrogen atom (the 2 to 1 transition) is in the UV part of the spectrum.

X-ray lines K(alpha)s come from 2->1 transition

K alpha lines are not in the x-ray spectrum for the lighter elements hydrogen and helium, ~121 nm for hydrogen and ~30 nm for helium.  This transition is in the UV region of the spectrum for these elements.

For the series of UV waves, the quantum numbers are n1=1 and n2=2,3,4...

This statement is true for the hydrogen atom.  We know the OP is talking about the hydrogen atom because he provided the equation to solve for the wavelengths for the hydrogen atom.
All transitions to the n=1 are in the UV region.  Once again look up the Lymann series, or plug in the numbers into the equation the OP provided, you'll see.

Valdo