[son012189]

Determine Kp at 298 K for the reaction 2CH4(g) ↔ C2H2(g) + 3H2(g), given the following experimental data at 298 K.
CH4(g) + H2O(g) ↔CO(g) + 3H2(g)    Kp = 1.8 x 10-25

2C2H2(g) + 3O2(g)↔ 4CO(g) + 2H2O(g)     Kp = 1.6 x 102

H2(g) + ½ O2(g) ↔H2O(g)    Kp = 1.2 x 1040

I don't know the concentrations of CH4, C2H2, H2 and etc. How am I supposed to calculate Kp. In order to calculate Kp, I have to the concentrations of the compounds in the equation. I tried subtracting the equations from one another and that didn't do anything. I need to know how to solve this problem

[champ]

u have to add all the equations to get the final equation which is 2CH4(g)---->C2H4(g)+3H2(g)

CH4(g) + H2O(g) ↔CO(g) + 3H2(g)   Kp = 1.8 x 10-25 times by 2

2C2H2(g) + 3O2(g)↔ 4CO(g) + 2H2O(g)     Kp = 1.6 x 102 first reverse the equation and then *1/2

H2(g) + ½ O2(g) ↔H2O(g)    Kp = 1.2 x 1040 times by 3

it willl give you the right Equation which is stated above..

[champ]

i hope u can do the rest....