So, because Sodium Nitrate has a Molar mass of 84.9947 g/mol, and Sodium Nitrite has a Molar mass of 69.00 g/mol, and I know that 850 mg Na nitrate + 10 ml H20 = a 1.00 M solution, then that means a 1 N solution of Na Nitrite would be 690 mg + 10 ml H20. I wonder if that's how I was supposed to figure that problem out...