[oceanmd]

What is the limiting reagent and how much excess reagent is there and how much Aluminum Phosphate is produced if 25.0 g of Al reacts with 100 g of H3PO4?

Is this equation correct 2Al+2H3PO4=2AlPO4+3H2

Al-limiting reagent
H3PO4 is in excess by 8.82g
113.41 g AlPO4 is produced

Please tell me if this makes any sense.

Thank you

[ARGOS++]

Dear Oceanmd;

Al as limiting is ok!
For all other: If I would use the wooden calculator, then I could probably accept your results.
Can you do it a little more precise? - Only for you, not for me.

Good Luck!
                    ARGOS⁺⁺

[oceanmd]

25 g Al /26.982= 0.9265 mol Al
100 g H3PO4 / (3 x 1.01+30.974+4 X 16) = 100/98 = 1.02 mol H3PO4
1.02-0.9265 = 0.0935 mol H3PO4
0.0935 x 98 = 9.163 g H3PO4 in excess
0.9265 x 121.95 = 112.99 g AlPO4 is produced.

Argo, Is this any better?

Thanks


H3PO4 is in excess by 8.82g
113.41 g AlPO4 is produced

[ARGOS++]

Dear Oceanmd;

That’s very much better!

But tell me, Why you forgot to delete the last two lines?
Otherwise I would say:  Nearly perfect!

Good Luck!
                    ARGOS⁺⁺

[oceanmd]

Calculate the number of grams of H2SO4 produced when 27 g of H2o reacts with 10 g SO
H2O+SO3=H2SO4

SO3-limiting
12.26 g H2SO4 produced.

This is the last problem for tonight. Is it correct.

Thank you, ARGO.

[ARGOS++]

Dear Oceanmd;

It is ok.
I believe too, that it is time for your bed, because you forgot the index “3” (it’s SO₃ not SO) and you forgot how much Excess water you have.

And sorry:   My “Name” ends with an “s”.
Have a good Sleep!

Good Luck!
                    ARGOS⁺⁺

[oceanmd]

ARGOS,

Thank you for all your help.