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Topic: ideal gas law and converting units  (Read 3365 times)

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Offline joules

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ideal gas law and converting units
« on: March 02, 2008, 01:43:19 PM »
Sometimes the simplist things slip me up.  As part of a multistep question, I need to calulate the density of an ideal gas.

Knowing that density = RT/P and using R = 287 J/kg K , T = 298 K and P = 1 atm = 101325 Pa

Density = 101325 Pa/ (287 J/kg K)(298 K) = 1.1847 Pa kg/J

Does 1.1847 Pa kg/J = 1.1847 kg/m^3?

I can't find a conversion for Pa kg/J anywhere online so this makes me question my work.


Offline joules

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Re: ideal gas law and converting units
« Reply #1 on: March 02, 2008, 02:02:50 PM »
Figured it out.  I need to use the gas constant R in m^3 atm/mol K and multiply my denisty by the mw to get the proper units of kg/m^3

Offline Yggdrasil

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Re: ideal gas law and converting units
« Reply #2 on: March 02, 2008, 02:11:34 PM »
1 N = 1 kg m s-2
1 Pa = 1 N m-2 = 1 kg m-1 s-2
1 J = 1 N m = 1 kg m2 s2

You can remember these formulas from the definitions of force, presssure, and work (energy):

Force (N) = mass (kg) * acceleration (m s-2)
Pressure (Pa) = Force (N)/Area (m2)
Work (J) = Force (N) * Distance (m)

Another useful conversion is the fact that:
1 L atm = 101.3 J

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