September 28, 2024, 11:36:37 AM
Forum Rules: Read This Before Posting


Topic: frequency  (Read 3942 times)

0 Members and 1 Guest are viewing this topic.

Offline chay722

  • Regular Member
  • ***
  • Posts: 52
  • Mole Snacks: +0/-3
frequency
« on: March 12, 2008, 08:54:33 PM »
The one equation you could use to determine the frequency of the photon emitted by the electron is:
a) E2-E1=hv
b) E=hv
c) c=v(lambda)
d) c=h(lambda)

I would think choice b and c would both work but I am unsure. Thanks for any help.

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: frequency
« Reply #1 on: March 12, 2008, 09:05:37 PM »

Dear Chay722;

Sorry!,    ─   You took twice the wrong!
(But there it’s not much left.)


Good Luck!
                    ARGOS++


Offline chay722

  • Regular Member
  • ***
  • Posts: 52
  • Mole Snacks: +0/-3
Re: frequency
« Reply #2 on: March 12, 2008, 09:20:48 PM »
so would choice a be correct? I see it is the only choice left with v in it.

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: frequency
« Reply #3 on: March 12, 2008, 09:29:05 PM »

Dear Chay722;

Precisely!
Do you know why?,    ─   You may read below the Question: “Why Einstein meets Beer-Lambert” on:   "Spectroscopy FAQ
(see: Citation from N.J. Turro.)

Good Luck!
                    ARGOS++


Offline chay722

  • Regular Member
  • ***
  • Posts: 52
  • Mole Snacks: +0/-3
Re: frequency
« Reply #4 on: March 12, 2008, 09:38:50 PM »
thank you very much for that link.

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: frequency
« Reply #5 on: March 12, 2008, 09:46:01 PM »

Dear Chay722;

You’re welcome!   ─   Soon again.


Good Luck!
                    ARGOS++


Sponsored Links