An 80-pound ice sculpture is the centerpiece of a table under a tent during an outdoor party. It was kept in a 0 Celsius degree freezer until 12:00 noon when the party began. The tent temperature was 80 degrees Fahrenheit.
Specific heat of water = 4.184 J / g K
Hvap(H2O) = 2260 J / g
Hfus(H2O) = 333 J / g
1 kcal = 4184 J
A. How much energy is necessary to completely melt the sculpture?
B. How much energy is required for the melted ice to evaporate?
C. After reaching 70 degrees Fahrenheit, how much energy must be removed to refreeze the melted ice?
D. At 3:00 p.m., how much of the ice sculpture has melted if 80 degrees Fahrenheit was equivalent to 126.5 W?
I know I have to convert the temperature to Celsius and convert the pounds to grams. I used the equation Q=Cp x M x Change in temp. This is a practice question for a chemistry competition next week. Any help is appreciated. Thanks!
q= Cp x m x change in temp
12,094,560 = 4.184 x 36320g x n
n= 79.5889 degrees
This is all I can do >.<