2. What is the total concentration of NO3- when 2.50 mL of 0.30 M Fe(NO3)3 in 0.10M HNO3 in 0.10M HNO3 is diluted to 10.0 mL with water?
a. 0.75 M NO3- b. 0.10M NO3- c. 0.19 M NO3- d. 0.08 M NO3- e. 0.21 M NO3-
I took CFe = .30M x (2.50ml/10ml) x 3 = .225 M NO3...which is close to the answer of 0.21 M NO3-
ANy idea?
The answer is e.