[Ch3m1$try]

Dear Chemists and students

I am having an issue finding out an answer to this solution, well here it is.

What is the pH of a 2.0M solution of HCI?

See if you can find an answer well this is what i have so far(as an attempt) below

-Log(2)=(-.301)

14-(-.301) = 14.301

Bear in mind this is my first attempt, and the chances of me being wrong are great.
 
See to it.

[enahs]

-Log(2)=(-.301)

Correct.
That is it. Walk away.

14-(-.301) = 14.301

Not sure why you are doing this.


Go back and restudy pH and such:
http://www.chembuddy.com/?left=pH-calculation&right=pH-definition
And more info/topics on the menu to the left.