So, I was learning about reaction mechanisms and the hydrolysis [specifically that it was nucleophilic substitution ] of halogenoalkanes.
I learned how primary and secondary HAs can undergo the one step mechanism where the OH group will substitute the halide, but when it came to tertiary HAs (which we dont need to know, but I was interested ) I now learn they dont undergo the same 1 step mechanism, but a 2 step instead.
Curious as to why, I learn its because tertiary HAs form particularly stable carbocations: again, why? Apparently methyl groups repel electron density from them, towards the C+ , thus neutralising out the charge somewhat.
Now Im fine and I understand it up til there, but I dont understand why methyl groups repel electrons: I asked my teacher, and he said it was something to do with the way the orbitals overlap in CH3 groups, but I lost it there.
Could anyone explain this to me? If not, its no big deal, honestly, Im just curious.