[GaryBusey]

k= 3,00

SO2(g) + NO2(g) <--> SO3(g) + NO(g)

Calculate the substance amount of NO which shall be added to 2,6 mol SO2 when the substance amount of SO3 is 1,2 mol at chemical equilibrium   

i dont have any key so i would realy like to se if i have made everything right.

My idea is to get 3/1 = 3 = k

[C][D]) / ([A][ b ])

([1,2][D]) / ([2,6][ b ]) = 3

(1.2*2,5)/(2,6*0,385) = 3

D(NO) = 2,5
B(NO2) = 0,385

Have i done right?

[Borek]

Try to reword your question, I can't make sense out of it