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Topic: preparing a solution  (Read 2971 times)

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Offline equation33

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preparing a solution
« on: May 21, 2008, 04:00:49 PM »
HI, just want to know if im doing this right. The question is the prepare a 1.5 M solution of calcium Nitrate. So i start by getting the MM(164g). I then guessed the amount of CA(No3)2 i would need. I chose 24g. So i then dissolved my 24g of calcium Nitrate in 0.100L solution. I copied an example out of my book and this is what i got
 1.46 M calcium Nitrate. Is this way right? and also is there a way i could calculate the grams i would need instead of guessing?

Offline macman104

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Re: preparing a solution
« Reply #1 on: May 21, 2008, 04:42:13 PM »
Well, 1.5M indicates how many moles of Ca(NO3)2 in 1 liter of solution?

So, if you have "x" moles to dissolve in 1 liter of solution, then you know how many grams that is.

If you only want 100 mL, that is 1/10 of 1 L, so, what would you divide your grams by...

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