[Cop J]

Problems:
Given the following pycnometer data:         Pycnometer is the flask and a one hole rubber stopper.

    * Weight of the water filled flask and stopper...     60.2555 g
    * Density of water used in experiment....     0.9932 g/cc
    * Weight of the flask, solid, and stopper....     132.0768 g
    * Weight of the EMPTY flask and stopper...     33.2351 g
    * Weight of the flask, solid, stopper, and water..     140.2725 g

CALCULATE:   
The WEIGHT of solid used   _______________ (e)
The VOLUME contained by the flask
enter (f) to 3 decimal places   _______________ (f)
The volume of water needed to fill the flask when the SOLID is in the flask
enter (g) to 3 decimal places    _______________ (g)
The VOLUME of the SOLID   _______________ (h)
The DENSITY of the SOLID   _______________ (i)

So far I got:

e = 98.8417 g
f = 27.205 cc
g = 8.251 cc

h, and i are killing me. Please if someone can offer some help that would greatly be appreciated!
Sorry to post this again but I really really need some help on these problems. I have to answer it by tonight. Someone here has to know how to do it. I just need a little help.

[Astrokel]

h: Imagine a solid being dropped into a flask filled with water. The water that is displaced when the solid is dropped into the flask is the volume of the solid, right? Same thing goes. Imagine now a solid with volume x is inside the flask without and water. If you need y more volume of water to fill up the flask(let's say volume of the flask is z), what is the volume of solid? Try to think mathematically.

 

[Padfoot]

i: Density is mass/volume
so simply use the mass you calculated in e) and the volume you get for i) and your done 

[Cop J]

I know but I need to find H first and I have no idea how to find H. Can anyone work out the problem for me so I can see it being done?

[Padfoot]

Astrokel post

[Borek]

As Astrokel already wrote - solid volume is that of displaced water. You know volume of water without solid in and voume with solid in.