[redskytonight820]

Hey... I'm sorry for asking a second question, but I wanted to check if what I have done so far is right.

Template strand of segment of double-strand DNA has sequence:

(5') CTT TGA TAA GGA TAG CCC TTC

1)
Give the base sequence of the mRNA that would be transcribed from this strand.

mRNA: 3' GAA ACU AUU CCU AUC GGG AAG

2)
Give amino acid sequence that is coded by the mRNA base sequence in 1), using only the first reading frame starting at the 5' end.


mRNA: 5' GAA GGG CUA UCC UUA UCA AAG
a.a:        GLU GLY LEU  SER LEU  SER LYS


3)
If the other (complementary) strand is used as a template for transcription, give the amino acid sequence of the resulting peptide, again starting from the 5' end and using only the first reading frame?



complementary strand: 3' GAA ACT ATT CCT ATC GGG AAG
                      mRNA: 5' CUU UGA UAA GGA UAG CCC UUC                             


But I don't know where the first reading frame here is... Is everything I have so far correct though?

Thanks!

[Yggdrasil]

Hey... I'm sorry for asking a second question, but I wanted to check if what I have done so far is right.

Template strand of segment of double-strand DNA has sequence:

(5') CTT TGA TAA GGA TAG CCC TTC

1)
Give the base sequence of the mRNA that would be transcribed from this strand.

mRNA: 3' GAA ACU AUU CCU AUC GGG AAG

Nucleic acid sequences should always be written in a 5'->3' direction.  The answer is correct, but you should just flip it around so that it is in the correct orientation.

2)
Give amino acid sequence that is coded by the mRNA base sequence in 1), using only the first reading frame starting at the 5' end.


mRNA: 5' GAA GGG CUA UCC UUA UCA AAG
a.a:        GLU GLY LEU  SER LEU  SER LYS

Correct

3)
If the other (complementary) strand is used as a template for transcription, give the amino acid sequence of the resulting peptide, again starting from the 5' end and using only the first reading frame?



complementary strand: 3' GAA ACT ATT CCT ATC GGG AAG
                      mRNA: 5' CUU UGA UAA GGA UAG CCC UUC                             


But I don't know where the first reading frame here is... Is everything I have so far correct though?

The first reading frame would just be having the first codon start on the first nucleotide in the sequence.

Thanks!
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[redskytonight820]

mRNA: 5' CUU UGA UAA GGA UAG CCC UUC

CUU = first reading frame then?

so it's LEU STOP STOP GLY STOP PRO  PHE

hmm so should I stop at Leucine, since afterwards is a STOP codon?

[victor]

yup, when it meet STOP codon, it should stop translating