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Topic: forgot how to do these its been 15 yrs  (Read 2557 times)

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Offline danny411

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forgot how to do these its been 15 yrs
« on: July 12, 2008, 12:43:37 AM »
30.0 g of potassium chloride , kcl, dissolves in 175 ml of water

calculate the kcl In M

i got 2.30 M

and for the ions the same

the other one was 50.0 ml solution Ca(No3)2 has a [No3] of 4.0 x10^-1. how many grams of ca(no3)2 has been dissolved?

i think i can divide 4.0 x 10^-1 /2 since the mole rations is 2

then ca(no3)2 is .200

do i divide this by 1.00 or 50.0 ?

maybe im lost can someone show me the way to do it ? step by step ?

Offline sameeralord

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Re: forgot how to do these its been 15 yrs
« Reply #1 on: July 12, 2008, 01:02:47 AM »
30.0 g of potassium chloride , kcl, dissolves in 175 ml of water

Concentration is= n/v

n=moles
v= volumes in litres

So first find the moles.

n=m/mr 

m=mass
mr=molar mass you find in the periodic table

After that divide the moles you found by 0.175

the other one was 50.0 ml solution Ca(No3)2 has a [No3] of 4.0 x10^-1. how many grams of ca(no3)2 has been dissolved?

I'm assuming 4.0 x10^-1 is M. Make a another equation like this.

Ca2+ + 2NO3- =Ca(NO3)2

First find the moles of  [No3]

n=cxv
   4.0 x10^-1 x 0.050

Now use mole ratios to find the moles of Ca(NO3)2
Times the moles you found by 1/2.

Now find the mass m=nxmr

 ;)


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