December 22, 2024, 02:26:44 AM
Forum Rules: Read This Before Posting


Topic: Absolute configuration on 2 biphenyls  (Read 4767 times)

0 Members and 1 Guest are viewing this topic.

Offline Lithium

  • Regular Member
  • ***
  • Posts: 16
  • Mole Snacks: +0/-0
Absolute configuration on 2 biphenyls
« on: July 23, 2008, 02:26:37 PM »
Can you have absolute configuration on a biphenyl?  If so how do decided the R and S  I have a Cl going up on the top and a Cl going down on the other.

Offline azmanam

  • Chemist
  • Sr. Member
  • *
  • Posts: 1416
  • Mole Snacks: +160/-24
  • Mediocrity is a handrail -Charles Louis d'Secondat
Re: Absolute configuration on 2 biphenyls
« Reply #1 on: July 23, 2008, 03:21:08 PM »
not unless there's atropisomerism.  Wedges and hashes (if they're directly attached to the aromatic ring) are meaningless, because they're sp2 carbons.

R and S are not the right identifiers.  I think for atropisomers, the identifiers are P and M, but I don't remember the rules off hand.  + and - also work.

http://www.cem.msu.edu/~reusch/VirtTxtJml/sterism3.htm#isom19b
http://en.wikipedia.org/wiki/Atropisomerism
Knowing why you got a question wrong is better than knowing that you got a question right.

Offline azmanam

  • Chemist
  • Sr. Member
  • *
  • Posts: 1416
  • Mole Snacks: +160/-24
  • Mediocrity is a handrail -Charles Louis d'Secondat
Re: Absolute configuration on 2 biphenyls
« Reply #2 on: July 23, 2008, 03:44:33 PM »
see attached for what I have in my notes from 1st semester organic in grad school. (it's for allenes, but the analysis is the same for any bond of hindered rotation)

http://en.wikipedia.org/wiki/Axial_chirality
http://en.wikipedia.org/wiki/Allenes
http://goldbook.iupac.org/A00547.html
Knowing why you got a question wrong is better than knowing that you got a question right.

Sponsored Links