My plan is
Add marble chips to some HCl until they stop reacting and there is some left at the bottom of the beaker.
Filter and throw away the excess CaCO
3. The solution should be neutral by now
CaCO
3 + 2HCl --> CaCl
2 + CO
2 + H
2O
Boil the solution down until there is little enough to put into a flat dish and to dry it off in an oven.
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For my electrolysis setup I'm gonna use a 12v adjustable DC adaptor and carbon graphite rods from inside the big square batteries that are used in torches for the electrodes.
There will be about 4/5 cathodes depending on how many I can get and only 1 or 2 anodes. Im using more cathodes so I'm able to pick up more Ca at once.
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Melt the
CaCO3 CaCl2 (takes near 800ºC) and place the electrodes into it then turn it on.
Do this outside or in a fume cupboard!! Cl
2 gas will be released, this is poisonous and if inhaled. As Cl
2 is heavier than air it will fall towards the ground.
Cathode equation:
Ca
2+ + 2e -> Ca
Anode equation:
2Cl
- -> Cl
2 + 2e
Questions:
What would the erosion on the electrodes be like? Would there be a better choice for this experiment? (I wonder how much some platinum rods would cost...)
Are my equations right?
Suggestions and comments welcome
EDIT: Just fixing those sub things