Will PbBr2 precipitate if student mixes .0001M of Pb2+ with 0.00005M Br- (Ksp of PbBr2 = 4.6x10-6)?
My problem with is when calculating the ion product. The math:
Ksp = [Pb2+][2Br]2
4.6x10-6 = .0001M * 0.00005M2
From this I see that the ion product (right hand side of math above) is less then the Ksp and there for no precipitant.
But, why is it that you have to do 0.00005M2 and not [2*0.00005M]2?
A general question, what will happen to Ksp with increasing temp (general case)?