I'm trying to work through some problems, and while I know that they aren't that difficult I just can't seem to get my head around it. Here they are:
You prepare a solution by adding 225 mL of .0500 M H2PO4- to 105 mL of .250 M HPO42-. Calculate the pH of the resulting solution.
Ka1=7.11x10^-3
Ka2=6.34x10^-8
Ka3=4.22x10^-13
A solution of o-phthalate is adjusted to pH 5.00. Calculate the fraction of o-phthalate that exists as H2P, HP-, and P2-.
Ka1=1.12x10^-3
Ka2=3.90x10^-6
Thanks in advance.