Quite a long one but I am stuck.
1. A mixture of 0.50 mol of ethanoic acid and 1 mol of ethanol was shaken for a long time to reach equilibrium. The whole mixture was titrated against 1.00 mol.dm-3 NaOH and 80cm3 was required.
By making use of the titration results, calculate:
A) How many moles of ethanoic acid remained in the mixture at equilibrium
B) How many moles of ethanoic acid had reacted
C) How many moles of ethanol were left in the mixture
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I have so far worked out that the equation is:
CH3COOH + CH3CH2OH <-> CH3COOCH2CH3 + H2O
And the number of moles of NaOH required was 0.08.
Initially I can see that the ethanoic acid to ethanol ratio is 1:2
Any help would be super.