[Dodecanone]

So I'm going to write the problem, say how far I am on it, and ask my questions

What is the maximum number of electrons that can be emitted if a potassium surface of work function 2.40 eV absorbs 3.25 x 10^-3 J of radiation at wavelength = 300nm? What is the kinetic energy and velocity of the electrons emitted?

What I have is:

E = βv - φ
Convert phi from eV to J = 3.84 x 10^-19

E = mv^2/2 = βν - φ

I'm not sure this is entirely right but I can get the Kinetic energy from E = βν - φ and then the velocity of an e- leaving from that.  But how can I get the max number of electrons?

Thanks!

[Astrokel]

hello,

to calculate, max no. of electrons emitted  = photons energy absorbed/work function and note that you are assuming one photon will collide with one electron in all collisions. your other answers look ok!

hope it helps some..