Hello,
Here is the problem,
I did an experiment and got the following information
1.Mass of crucible and lid 17.108 g
2.Mass of crucible,lid,and sample 17.259 g
3.Mass of sample 0.151 g
The sample was pieces of Mg ribbon. I subtracted 17.259-17.108=0.151
The sample was heated in air and heated a few times until completion.
4.Mass of crucible,lid, and product
1st mass measurement 17.268 g
2nd mass measurement 17.277 g
3rd mass measurement 17.276 g
5.Final mass of crucible,lid, and of product 17.276 g
6.Mass of product 0.017 g (I need your help here....I'm not sure about this calculation. I subtracted 17.276-17.259= 0.017, please advise
)
7. Determine the mole ratio of Mg to O, and thus the empirical formula, of the pure compound.
I also need your help here too
.
0.151 g Mg X 1 mol Mg/24.31 g Mg = 0.00621 mol Mg
0.017 g O X 1 mol O/16.00 g O = 0.00106 mol O ( Is the mass for Oxygen 0.017 g correct? Also, should I treat it as a diatomic molecule? So I would divide grams over 32.00 g and not 16.00 g)
0.00621 mol Mg/0.00106 = 5.85
Empirical Formula Mg6O------------
Please advise,
Thank you,
Lindsay