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Topic: Cu(OH)2 amphoteric or not?  (Read 15744 times)

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Offline n0m0r3l0v3_0k

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Cu(OH)2 amphoteric or not?
« on: October 06, 2008, 11:36:55 AM »
When I was highschool i studied that Cu(OH)2 is amphoteric but now my bro say that it's not amphoteric   ??? ??? Someone can explain this to me plz.
I remember : Cu(OH)2 + NaOH (concentrated) -> Na[Cu(OH)]4 but he said that his teacher not agree with this

Offline Borek

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Re: Cu(OH)2 amphoteric or not?
« Reply #1 on: October 06, 2008, 11:47:33 AM »
Cu(OH)2 + NaOH (concentrated) -> Na[Cu(OH)]4

My inorganic chemistry books confirm this reaction as occuring in hot and concentrated solutions of alkali metal hydroxides. Not much copper hydroxide dissolves this way, but some does. Unfortunately my books are in Polish so even if I will list titles they will be of no use for you (unless you are from Poland and you are in Vietnam only temporarily ;) )
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Offline n0m0r3l0v3_0k

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Re: Cu(OH)2 amphoteric or not?
« Reply #2 on: October 06, 2008, 02:17:00 PM »
Just one more question how abt Fe(OH)3 it's also amphoteric right ? NaOH(concentrated) + Fe(OH)3 -> Na[Fe(OH)4] ? Any condition ?

Offline nj_bartel

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Re: Cu(OH)2 amphoteric or not?
« Reply #3 on: October 06, 2008, 03:14:29 PM »
Many compounds are technically amphoteric, if you put them with a strong enough acid or base.  Most people wouldn't describe them as amphoteric though.

Offline Borek

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Re: Cu(OH)2 amphoteric or not?
« Reply #4 on: October 06, 2008, 04:20:22 PM »
NaOH(concentrated) + Fe(OH)3 -> Na[Fe(OH)4]

Very hot, and only very small amounts.

However, there are known salts like K2FeO4 - Fe(VI).
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