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Topic: Equilibrium Constant (FeNCS2+)  (Read 20738 times)

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Offline dada2

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Equilibrium Constant (FeNCS2+)
« on: October 15, 2008, 11:57:32 PM »
Hi,
I have a lab report due soon and despite immense effort, I just cant seem to understand how to do the calculations. The experiment reads:

A 5.0 mL vol of 0.002 M SCN- is mixed with 5.0 mL of 0.02 M Fe3+ to form FeNCS2+ complex. The equilibrium concentration is  7.0 x 10^-4 mol/L. Calculate the following:

* moles odf FeNCS2+ that form in reaching equilibrium
*moles of Fe that react to form the FeNCS2+ at equilibrium
*moles of SCN- that react to form the FeNCS2+ at equilibrium
* moles of Fe3+ (unreacted) at equilibrium
*moles of SCN- (unreacted) at equilibrium
*molar concentration of Fe3+ at equilibrium
*Equilibrium constant

I've already calculated the initial moles of SCN- to be 1.0 x 10^-5  and the initial moles of Fe3+ to be 1.0 x 10^-4
I believe the moles of Fe3+ (unreacted) at equilibrium is 9.0 x 10^-5 but then by that method, the moles of SCN- (unreacted) at equilibrium would be 0 which would make the equilibrium constant 0 which doesn't make sense. Any help would be appreciated. Thanks!

Offline Borek

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Re: Equilibrium Constant (FeNCS2+)
« Reply #1 on: October 16, 2008, 04:05:24 AM »
I believe the moles of Fe3+ (unreacted) at equilibrium is 9.0 x 10^-5

Why? That'll be if they all reacted to the end, you are given final (equilibrium) concentration.
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Offline dane502

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Re: Equilibrium Constant (FeNCS2+)
« Reply #2 on: October 16, 2008, 10:14:22 AM »
Hi dada2

A 5.0 mL vol of 0.002 M SCN- is mixed with 5.0 mL of 0.02 M Fe3+ to form FeNCS2+ complex. The equilibrium concentration is  7.0 x 10^-4 mol/L.

The equilibrium concentration of Fe3+, SCN- or FeSCN2+?

Assuming that it is equilibrium concentration FeSCN2+, convince yourself that the following is true:

[Fe3+]eq = [Fe3+]0 - [FeSCN2+]eq

[SCN-]eq = [SCN-]0 - [FeSCN2+]eq

where:

  • [Fe3+]0 is the inital concentration of Fe3+
  • [SCN-]0 is the inital concentration of SCN-
  • [Fe3+]eq is the equilibrium concentration of Fe3+
  • [SCN-]eq is the equilibrium concentration of SCN-
  • [FeSCN2+]eq is the equilibrium concentration FeSCN2+

This way you should not compute any concentration to be 0! 

This goes also for moles - you should not have a hard time rewriting the expressions from computing concentrations at equilibrium to computing amount of substances - moles as you call it - at equilibrium.
« Last Edit: October 16, 2008, 10:29:37 AM by dane502 »

Offline AWK

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Re: Equilibrium Constant (FeNCS2+)
« Reply #3 on: October 16, 2008, 11:39:15 AM »
A 5.0 mL vol of 0.002 M SCN- is mixed with 5.0 mL of 0.02 M Fe3+ to form FeNCS2+ complex. The equilibrium concentration is  7.0 x 10^-4 mol/L.
The equilibrium concentration of which ion?

Write down a stoichiometry of reaction first
AWK

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