Entropy change during formation of Be
2+aq from Be
aq can be assumed to be 0, so that
During Be
aq Be
2+aq +2e
-,
E= :delta: H
sublimation + :delta: H
ionization 1 + :delta: H
ionization 2 + :delta: H
hydrationAlso, your statement is contradictory:
"better reducing agent(though it has less negative electrode reduction value)."