[prncess23]

2.1g of cyclohexene is reacted with 6.0g of bromine to yield 2.0 g 1,2-dibromocyclohexane.

a) what is the expected product?
b) which is the limiting reagent
c) what is the expected yield?
d) what is the percent yield?

[Astrokel]

hi prncess23,

you have to show some work so we know where you have gone wrong. Start off with balanced equation then work with moles.

[prncess23]

i got this far...

i got
2.1 g cyclohexene (1 mole/82.14g)=0.026 moles cyclohexene
6.0g br2(1 mole/159.81g)=0.038moles Br2

since it is a 1:1 ratio moles Cyclohexene=moles 1,2-dibromocyclohexane.

then to determine the limiting reganent i did:
0.026moles cyclohexene (.038moles br2)=0.000988 moles Br2 required for completion.

0.038moles br2 (.026moles)= 0.000988 moles of cyclohexene required for completion...


now...im stuck..

[Borek]

then to determine the limiting reganent i did:
0.026moles cyclohexene (.038moles br2)=0.000988 moles Br2 required for completion.

No, that's not the correct way.

Do you know how to read reaction equation?

If 1 mole of cyclohexene reacts with 1 mole of bromine, how many moles of bromine react with 0.026 moles of cyclohexene?

[prncess23]

i know how to read an equation.

the answer to your question:
0.026 moles of cyclohexene(1 mole/159.81g)=0.0001627 moles bromine...right???