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Topic: I have to find a percentageof a formula in a mixture  (Read 3485 times)

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Offline Tony30

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I have to find a percentageof a formula in a mixture
« on: November 01, 2008, 11:06:20 PM »
Street Heroin, C21H23O5N x HCL was diluted with mannitol, C6H14O06. If .0648 g of this mixture is completely combusted in pure oxygen gas, .07250 mL of gaseous carbon dioxde (denisty= 1.80 g/L) are formed. What is the pecentage of heroin in the mixture.
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Offline Borek

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Re: I have to find a percentageof a formula in a mixture
« Reply #1 on: November 02, 2008, 04:22:00 AM »
Please show your work.
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Offline Tony30

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Re: I have to find a percentageof a formula in a mixture
« Reply #2 on: November 02, 2008, 09:22:07 AM »
C6H14O6 + C21H23O5N*HCl + O2  = 21CO2
 these combined is .0648 g                .1305 g after multiplying density by volume.

This is good and then i get lost
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Offline sjb

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Re: I have to find a percentageof a formula in a mixture
« Reply #3 on: November 02, 2008, 02:37:11 PM »
Can you write a balanced equation for the combustion?
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Offline Borek

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Re: I have to find a percentageof a formula in a mixture
« Reply #4 on: November 02, 2008, 03:47:30 PM »
Separately for each compound.
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