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How do you balance this equation? it's very hard.

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Offline au5467

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balancing equation
« on: November 03, 2008, 01:12:22 AM »
Okay, this was the referance that I was looking at.

"Test for the presence of phosphate ion, PO43-. Add 1ml of 6M HNO3 to 1ml of 0.5M Na2HPO4. Then add 1ml of 0.5M (NH4)2MoO4 and stir thoroughly. A precipitate forms, (NH4)3PO4•12MoO3, which indicates the presence of phosphate." -Experiment 35: Spot Tests for Some Common Ions

I set up the equation,
2HNO3 + Na2HPO4 --> 2NaNO3 + H3PO4

and set this up...this is the equation that I'm struggling with:
H3PO4 + (NH4)2MoO4 --> (NH4)3PO4• 12MoO3

the first equation that I "solved" can be wrong, so please tell me if there is error.

I'm soo confused right now...  ??? how do you balance the last equation? Or how do you get the net ionic equation from this question? I've spent many, many hours and I still can't figure it out.
« Last Edit: November 03, 2008, 01:36:32 AM by katejiwon »

Offline AWK

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Re: balancing equation
« Reply #1 on: November 03, 2008, 02:42:31 AM »
H3PO4 + 12(NH4)2MoO4 + 21HNO3 = (NH4)3PMo12O40 21NH4NO3 + 12H2O
AWK

Offline Hello12

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Re: balancing equation
« Reply #2 on: November 23, 2008, 11:05:17 AM »

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