One, Fe2(SO4)3 does not have enough energy to pull Cu out its compound (according to the reactivity series)
Two, H2SO4 can't react with Fe2(SO4)3 because the Fe 2+ ion is stronger than H2So4(covalent bonds) so it doesnot occur
Three, you are twice wrong.
H
2SO
4 doesn't react here with Fe
2(SO
4)
3, it takes care of oxygen from copper oxide. And Fe(II) won't work, but Fe(III) does is quite strong oxidizer, routinely used to etch copper from printed circuit boards (although it seems to me that it is lately replaced by other, greener methods).