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Topic: Theoretical Yield and Acid-Base rxn  (Read 12539 times)

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Offline Igloo61

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Theoretical Yield and Acid-Base rxn
« on: November 19, 2008, 06:32:40 PM »
I'd love if someone would help me with this, I want to know if my answers are correct.

I. For the reaction shown, compute the theoretical yield of product (in moles) for each of the following initial amount of reactants.

2Mn(s) + 2O2(g) ---> 2MnO2(s)

1. 3 mol Mn, 3 mol O2
Answer: 3 mol MnO2(s)

2. 4 mol Mn, 7 mol O2
Answer: 4 mol MnO2(s)

3. 27.5 mol Mn, 43.8 mol O2
Answer: 27.5 mol MnO2(s)

II. Complete and Balance each of the following equations for acid-base reactions.

1. H2SO4(aq) + Ca(OH)2(aq) ---> 2H2O(l) + CaSO4(aq)

2. HClO4(aq) + KOH(aq) ---> KClO4(aq) + H2O(l)

3. H2SO4(aq) + 2NaOH(aq) ---> Na2SO4(aq) + 2H2O(l)

Thank you very much for your time.

Offline Astrokel

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Re: Theoretical Yield and Acid-Base rxn
« Reply #1 on: November 20, 2008, 12:27:38 AM »
That's all correct, good work! ;D

Quote
2Mn(s) + 2O2(g) ---> 2MnO2(s)
Is there a need to add 2? It's already balanced
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline AWK

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Re: Theoretical Yield and Acid-Base rxn
« Reply #2 on: November 20, 2008, 12:54:35 AM »
This is only comment!
Two of salts, namly CaSO4 and KClO4 are sparingly soluble then you can also use (s) instead of (aq).
AWK

Offline Igloo61

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Re: Theoretical Yield and Acid-Base rxn
« Reply #3 on: November 20, 2008, 01:06:25 AM »
Thanks guys, I appreciate it.

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