December 23, 2024, 12:46:12 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: How much oxygen is produced by the decomposition of 6.54 g of KClO3 ?  (Read 6384 times)

0 Members and 1 Guest are viewing this topic.

Offline jacquelinehang

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
How much oxygen is produced by the decomposition of 6.54 g of KClO3 ?
« on: January 14, 2009, 09:11:03 PM »
How many molecules of oxygen are produced by the decomposition of 6.54 g of potassium chlorate (KClO3)? 2KClO3 (s) -----> 2KCl(s) + 3O2(g)

I don't understand this question. Can someone PLEASE tell me the correct way to do it? Don't just give me the answer! Thanks.
« Last Edit: January 27, 2009, 06:33:23 AM by geodome »
Logged

Offline Mitch

  • General Chemist
  • Administrator
  • Sr. Member
  • *
  • Posts: 5298
  • Mole Snacks: +376/-3
  • Gender: Male
  • "I bring you peace." -Mr. Burns
    • Chemistry Blog
Re: This has been driving me CRAZY!!!!
« Reply #1 on: January 14, 2009, 11:08:47 PM »
It looks like your equation is balanced. Start by figuring out how many moles of of KClO3 you have. Do you remember how to do that?
Logged
Most Common Suggestions I Make on the Forums.
1. Start by writing a balanced chemical equation.
2. Don't confuse thermodynamic stability with chemical reactivity.
3. Forum Supports LaTex
Pages: [1]   Go Up
« previous next »
Sponsored Links