Whether the proton nmr spectrum given is 1st order or 2nd order depends on how close (dv) is the two chemical shift of the two chemically non-equivalent protons. If dv/J is greater than 10, then it is a first order situation. If dv/J is less than 10, then it is a second order situation. In second order situation, you are difficult to predict the connectivity of protons due to peak overlapping (e.g. distorted doublet, triplet etc.) seen in 1st order spectrum. For example, benzene. Hence, we would use alphabatical order to differientiate 1st order and 2nd order. For A2X2 system, it is obviously first order. For ABCD system, it is obviously second order. Is it clear?