Question
Hydrofluoric acid, HF, is a weak acid with an acid dissociation constant, Ka, of [6.6 * 10^-4]
a) Explain whether a 0.1M acetic acid or 0.1M hydrofluoric acid will have a lower pH value.
(Ka of acetic acid = 1.8*10^-5) my explanation:
As Ka is bigger, the stronger the acid. Since Ka of HF is higher, therefore the pH value of HF will be lower.
b)should a solution of NaF be acidic, basic or neutral? Explain your answer.my explanation:
NaF
Na+(do not undergo salt hydrolysis) + F-
F- + H2O
HF + OH-
.:. the solution of NaF is basic
c) If a 325ml solution contains 0.8M HF, what is the mass of NaF required to prepare a buffer soltuin with pH 3.5?my answer:
pH = pKa + log (salt/acid)
3.5 = -lg(6.6*10^-4) + lg (salt/0.
molarity of salt (NaF) = 1.67M
No. of moles of NaF = 1.67M * 0.325L = 0.543moles
Mr of NaF = 19+23 = 42
Mass of NaF = 42*0.543 = 22.8g
d)with the help of an eqn, explain what happens when a small amount of NaOH is added to the solution in (c).NaOH + HF
NaF + H2O
NaF
Na+ + F-
F- + H2O
HF + OH-