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Topic: C= C (dehalogenation of compound)  (Read 4386 times)

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Offline timchai

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C= C (dehalogenation of compound)
« on: March 10, 2009, 01:19:21 AM »
i want to ask if i am correct, and also which one has higher stability
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Offline azmanam

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Re: C= C (dehalogenation of compound)
« Reply #1 on: March 10, 2009, 07:40:27 AM »
sounds good
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Offline lutesium

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Re: C= C (dehalogenation of compound)
« Reply #2 on: March 10, 2009, 04:52:09 PM »
The first would be the major product as Markovnikov Rules!!!


Lutesium...
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Offline azmanam

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Re: C= C (dehalogenation of compound)
« Reply #3 on: March 10, 2009, 05:38:11 PM »
eh, both are trisubstituted.  the first is the major product because benzyllic protons are more acidic.
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Offline cundi

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Re: C= C (dehalogenation of compound)
« Reply #4 on: March 11, 2009, 03:50:28 AM »
Quote from: lutesium on March 10, 2009, 04:52:09 PM
The first would be the major product as Markovnikov Rules!!!


Lutesium...

Markonijov rules in a elimination reaction? Are you sure?
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Offline macman104

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Re: C= C (dehalogenation of compound)
« Reply #5 on: March 11, 2009, 02:03:09 PM »
No, markovnikov is not the correct term.  It's the zaitsev product.  However, like azmanam said, both are trisubstituted, but the benzylic hydrogen is more acidic and easier to remove.
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Offline lutesium

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Re: C= C (dehalogenation of compound)
« Reply #6 on: March 14, 2009, 11:58:06 AM »
Thanx for the correction macman104 the correct term would be Zaitsev...


Lutesium...
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